What is expand (d^2y)/(d^2x)(x^3+y^3=1) ?

The solution to expand (d^2y)/(d^2x)(x^3+y^3=1) is x^2y+(y^4)/x =1

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expand (d^2y)/(d^2x)(x^3+y^3=1)

expand

\frac{d ^{2} y}{d ^{2} x} (x^{3} + y^{3} = 1)

x^{2} y + \frac{y ^{4}}{x} = 1

Solution steps

\frac{d ^{2} y}{d ^{2} x} (x^{3} + y^{3} = 1)

= \frac{d ^{2} y}{d ^{2} x} (x^{3} + 1 = y^{3})

Apply the distributive law:

a (b + c) = ab + a c

a = \frac{d ^{2} y}{d ^{2} x}, b = x^{3}, c = y^{3} = 1

\frac{d ^{2} y}{d ^{2} x} x^{3} + \frac{d ^{2} y}{d ^{2} x} y^{3} = 1

Expand

\frac{d ^{2} y}{d ^{2} x} x^{3} + \frac{d ^{2} y}{d ^{2} x} y^{3} : x^{2} y + \frac{y ^{4}}{x}

x^{2} y + \frac{y ^{4}}{x} = 1

(6 + 2 cos (x))^{2}

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\frac{L}{2 π} - \frac{( 4 - L ) ( 3 )}{18}

\frac{d y}{d x}, 6 x y + x^{2} - 2 y^{2} = 3

What is expand (d^2y)/(d^2x)(x^3+y^3=1) ?
The solution to expand (d^2y)/(d^2x)(x^3+y^3=1) is x^2y+(y^4)/x =1