What is expand (s-1)/((s-2)(s-3)) ?

The solution to expand (s-1)/((s-2)(s-3)) is (s-1)/(s^2-5s+6)

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expand (s-1)/((s-2)(s-3))

expand

\frac{s - 1}{( s - 2 ) ( s - 3 )}

\frac{s - 1}{s ^{2} - 5 s + 6}

Solution steps

\frac{s - 1}{( s - 2 ) ( s - 3 )}

Expand

(s - 2) (s - 3) : s^{2} - 5 s + 6

= \frac{s - 1}{s ^{2} - 5 s + 6}

(x - \frac{1}{2}) (x + \frac{3}{2})

(x - 2) (x + 2) [x - \frac{2}{x ^{2}} - 4 + \frac{1}{x} + 2 = \frac{1}{x} - 2]

\frac{1 + ln ( x )}{x ^{2} ( 1 - ln ( x ) ) ^{3}}

\frac{( x - 3 ) ( x + 6 )}{x + 7}

y^{'} (x) + \frac{( 1 - x ) y}{x}

What is expand (s-1)/((s-2)(s-3)) ?
The solution to expand (s-1)/((s-2)(s-3)) is (s-1)/(s^2-5s+6)