What is expand 12(2+(2i)/n)^2-9 ?

The solution to expand 12(2+(2i)/n)^2-9 is (-(48}{n^2}+39)+\frac{96)/n i

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expand 12(2+(2i)/n)^2-9

expand

12 (2 + \frac{2 i}{n})^{2} - 9

(- \frac{48}{n ^{2}} + 39) + \frac{96}{n} i

Solution steps

12 (2 + \frac{2 i}{n})^{2} - 9

Expand

12 (2 + \frac{2 i}{n})^{2} : 48 - \frac{48}{n ^{2}} + \frac{96}{n} i

= 48 - \frac{48}{n ^{2}} + \frac{96}{n} i - 9

Join

48 - \frac{48}{n ^{2}} + \frac{96}{n} i - 9 : - \frac{48}{n ^{2}} + \frac{96}{n} i + 39

= - \frac{48}{n ^{2}} + \frac{96}{n} i + 39

Rewrite in standard complex form:

(- \frac{48}{n ^{2}} + 39) + \frac{96}{n} i

= (- \frac{48}{n ^{2}} + 39) + \frac{96}{n} i

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What is expand 12(2+(2i)/n)^2-9 ?
The solution to expand 12(2+(2i)/n)^2-9 is (-(48}{n^2}+39)+\frac{96)/n i