What is expand ((x^3-8)(x-1))/(x^2-8) ?

The solution to expand ((x^3-8)(x-1))/(x^2-8) is (x^4-x^3-8x+8)/(x^2-8)

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expand ((x^3-8)(x-1))/(x^2-8)

expand

\frac{( x ^{3} - 8 ) ( x - 1 )}{x ^{2} - 8}

\frac{x ^{4} - x ^{3} - 8 x + 8}{x ^{2} - 8}

Solution steps

\frac{( x ^{3} - 8 ) ( x - 1 )}{x ^{2} - 8}

Expand

(x^{3} - 8) (x - 1) : x^{4} - x^{3} - 8 x + 8

= \frac{x ^{4} - x ^{3} - 8 x + 8}{x ^{2} - 8}

- \frac{h}{3} (- 3 y + \frac{2 h}{3})^{3} - (- \frac{h}{3})^{4}

(3 x y^{3} + 4 y) d x + (3 x^{2} y^{2} + 2 x) d y

\frac{2 s + 3}{( s + 1 ) ( 2 s ^{3} + 3 s ^{2} - 3 s - 2 )}

\frac{( 16 - x ) ^{2}}{4}

(x - Δ x)^{3}

What is expand ((x^3-8)(x-1))/(x^2-8) ?
The solution to expand ((x^3-8)(x-1))/(x^2-8) is (x^4-x^3-8x+8)/(x^2-8)