What is expand (2s+3)/((s+1)(2s^3+3s^2-3s-2)) ?

The solution to expand (2s+3)/((s+1)(2s^3+3s^2-3s-2)) is (2s+3)/(2s^4+5s^3-5s-2)

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expand (2s+3)/((s+1)(2s^3+3s^2-3s-2))

expand

\frac{2 s + 3}{( s + 1 ) ( 2 s ^{3} + 3 s ^{2} - 3 s - 2 )}

\frac{2 s + 3}{2 s ^{4} + 5 s ^{3} - 5 s - 2}

Solution steps

\frac{2 s + 3}{( s + 1 ) ( 2 s ^{3} + 3 s ^{2} - 3 s - 2 )}

Expand

(s + 1) (2 s^{3} + 3 s^{2} - 3 s - 2) : 2 s^{4} + 5 s^{3} - 5 s - 2

= \frac{2 s + 3}{2 s ^{4} + 5 s ^{3} - 5 s - 2}

\frac{( 16 - x ) ^{2}}{4}

(x - Δ x)^{3}

(x^{2} - \frac{2}{x})^{4}

(2 A x + B) e^{x} + e^{x} (A x^{2} + B x)

\frac{( 6 - x ) ^{2}}{9}

What is expand (2s+3)/((s+1)(2s^3+3s^2-3s-2)) ?
The solution to expand (2s+3)/((s+1)(2s^3+3s^2-3s-2)) is (2s+3)/(2s^4+5s^3-5s-2)