What is expand ((6-x)^2)/9 ?

The solution to expand ((6-x)^2)/9 is (x^2)/9-(4x)/3+4

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expand ((6-x)^2)/9

expand

\frac{( 6 - x ) ^{2}}{9}

\frac{x ^{2}}{9} - \frac{4 x}{3} + 4

Solution steps

\frac{( 6 - x ) ^{2}}{9}

(6 - x)^{2} = 36 - 12 x + x^{2}

= \frac{36 - 12 x + x ^{2}}{9}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{36 - 12 x + x ^{2}}{9} = \frac{36}{9} - \frac{12 x}{9} + \frac{x ^{2}}{9}

= \frac{36}{9} - \frac{12 x}{9} + \frac{x ^{2}}{9}

Divide the numbers:

\frac{36}{9} = 4

= 4 - \frac{12 x}{9} + \frac{x ^{2}}{9}

Cancel

\frac{12 x}{9} : \frac{4 x}{3}

= 4 - \frac{4 x}{3} + \frac{x ^{2}}{9}

Rewrite in standard form

= \frac{x ^{2}}{9} - \frac{4 x}{3} + 4

a (arctan (wT) - arctan (w Y))

a^{2} b^{2} - c^{2} d^{2} (sin (2 α) + 1)

(1 - L) \cdot (1 - t) \cdot w

(x + 2 i)^{2} (x - 2 i)

\frac{x}{( x + 1 ) ( x - 1 )}

What is expand ((6-x)^2)/9 ?
The solution to expand ((6-x)^2)/9 is (x^2)/9-(4x)/3+4