What is expand x^{1/2}(x^2-2x+1) ?

The solution to expand x^{1/2}(x^2-2x+1) is x^{5/2}-2x^{3/2}+x^{1/2}

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expand x^{1/2}(x^2-2x+1)

expand

x^{\frac{1}{2}} (x^{2} - 2 x + 1)

x^{\frac{5}{2}} - 2 x^{\frac{3}{2}} + x^{\frac{1}{2}}

Solution steps

x^{\frac{1}{2}} (x^{2} - 2 x + 1)

Apply the distributive law:

m (a + b + c) = ma + mb + m c

x^{\frac{1}{2}} (x^{2} - 2 x + 1) = x^{\frac{1}{2}} x^{2} + x^{\frac{1}{2}} (- 2 x) + x^{\frac{1}{2}} \cdot 1

= x^{\frac{1}{2}} x^{2} + x^{\frac{1}{2}} (- 2 x) + x^{\frac{1}{2}} \cdot 1

x^{\frac{1}{2}} x^{2} = x^{\frac{5}{2}}

x^{\frac{1}{2}} (- 2 x) = - 2 x^{\frac{3}{2}}

x^{\frac{1}{2}} \cdot 1 = x^{\frac{1}{2}}

= x^{\frac{5}{2}} - 2 x^{\frac{3}{2}} + x^{\frac{1}{2}}

\frac{5}{x ^{2} \cdot ( x ^{2} + 2 x + 6 )}

2 (6 - 2)

m tan (x) \cdot (cos (x) + cot (x))

\frac{1}{2} (- \frac{1}{7} cos (7 x) - \frac{1}{5} cos (5 x))

6 (5 + 9)

What is expand x^{1/2}(x^2-2x+1) ?
The solution to expand x^{1/2}(x^2-2x+1) is x^{5/2}-2x^{3/2}+x^{1/2}