What is expand x^2(2cos(x)-4xsin(x)-x^2cos(x)) ?

The solution to expand x^2(2cos(x)-4xsin(x)-x^2cos(x)) is 2x^2cos(x)-4x^3sin(x)-x^4cos(x)

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expand x^2(2cos(x)-4xsin(x)-x^2cos(x))

expand

x^{2} (2 cos (x) - 4 x sin (x) - x^{2} cos (x))

2 x^{2} cos (x) - 4 x^{3} sin (x) - x^{4} cos (x)

Solution steps

x^{2} (2 cos (x) - 4 x sin (x) - x^{2} cos (x))

Apply the distributive law:

m (a + b + c) = ma + mb + m c

x^{2} (2 cos (x) - 4 x sin (x) - x^{2} cos (x)) = x^{2} \cdot 2 cos (x) + x^{2} (- 4 x sin (x)) + x^{2} (- x^{2} cos (x))

= x^{2} \cdot 2 cos (x) + x^{2} (- 4 x sin (x)) + x^{2} (- x^{2} cos (x))

Simplify

x^{2} \cdot 2 cos (x) + x^{2} (- 4 x sin (x)) + x^{2} (- x^{2} cos (x)) : 2 x^{2} cos (x) - 4 x^{3} sin (x) - x^{4} cos (x)

= 2 x^{2} cos (x) - 4 x^{3} sin (x) - x^{4} cos (x)

(x + e^{x})^{2}

e^{3 x} (4 - 2 x) - 2

- \frac{3}{16} (- \frac{19}{4} + (- \frac{3}{4} ln (\frac{9}{57 - 64 x})))

(2 sin (2 t)) (1 + 2 sin^{2} (t))

What is expand x^2(2cos(x)-4xsin(x)-x^2cos(x)) ?
The solution to expand x^2(2cos(x)-4xsin(x)-x^2cos(x)) is 2x^2cos(x)-4x^3sin(x)-x^4cos(x)