What is expand (3(x^2-x+6))/(4(x^2-9)) ?

The solution to expand (3(x^2-x+6))/(4(x^2-9)) is (3x^2-3x+18)/(4x^2-36)

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expand (3(x^2-x+6))/(4(x^2-9))

expand

\frac{3 ( x ^{2} - x + 6 )}{4 ( x ^{2} - 9 )}

\frac{3 x ^{2} - 3 x + 18}{4 x ^{2} - 36}

Solution steps

\frac{3 ( x ^{2} - x + 6 )}{4 ( x ^{2} - 9 )}

Expand

4 (x^{2} - 9) : 4 x^{2} - 36

= \frac{3 ( x ^{2} - x + 6 )}{4 x ^{2} - 36}

Expand

3 (x^{2} - x + 6) : 3 x^{2} - 3 x + 18

= \frac{3 x ^{2} - 3 x + 18}{4 x ^{2} - 36}

\frac{3 ( 4 x ^{2} + 2 - 5 x )}{4}

(x^{3} + \frac{10}{x ^{2}})^{10}

18 (3 sin (x) - 4 sin^{3} (x))

(x - 5 - 2) (x - 5 + 2)

(x - 3) (x + 2) (x - 2) (x - 2) (x + 2)

What is expand (3(x^2-x+6))/(4(x^2-9)) ?
The solution to expand (3(x^2-x+6))/(4(x^2-9)) is (3x^2-3x+18)/(4x^2-36)