What is expand (2(3x-2))/((x+1)^3) ?

The solution to expand (2(3x-2))/((x+1)^3) is (6x-4)/(x^3+3x^2+3x+1)

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expand (2(3x-2))/((x+1)^3)

expand

\frac{2 ( 3 x - 2 )}{( x + 1 ) ^{3}}

\frac{6 x - 4}{x ^{3} + 3 x ^{2} + 3 x + 1}

Solution steps

\frac{2 ( 3 x - 2 )}{( x + 1 ) ^{3}}

(x + 1)^{3} = x^{3} + 3 x^{2} + 3 x + 1

= \frac{2 ( 3 x - 2 )}{x ^{3} + 3 x ^{2} + 3 x + 1}

Expand

2 (3 x - 2) : 6 x - 4

= \frac{6 x - 4}{x ^{3} + 3 x ^{2} + 3 x + 1}

\frac{x - 1}{( x - 5 ) ^{2}}

\frac{1}{( 1 + t ^{2} ) ( t ^{2} + s ^{2} )}

(z + 3 z - 2)^{2}

\frac{2}{( e ^{t} + e ^{- t} ) ^{2}}

What is expand (2(3x-2))/((x+1)^3) ?
The solution to expand (2(3x-2))/((x+1)^3) is (6x-4)/(x^3+3x^2+3x+1)