What is expand (3x-8y-18=0,)(3x-8y+1=0) ?

The solution to expand (3x-8y-18=0,)(3x-8y+1=0) is 9x^2-24xy+3x=0

Popular >

expand (3x-8y-18=0,)(3x-8y+1=0)

expand

(3 x - 8 y - 18 = 0,) (3 x - 8 y + 1 = 0)

9 x^{2} - 24 x y + 3 x = 0

Solution steps

(3 x - 8 y - 18 = 0,) (3 x - 8 y + 1 = 0)

= (3 x - 8 y - 18 \cdot 0 =,) (3 x - 8 y + 1 \cdot 0 =)

Distribute parentheses

3 x \cdot 3 x + 3 x (- 8 y) + 3 x \cdot 1 = 0 + (- 8 y) \cdot 3 x + (- 8 y) (- 8 y) + (- 8 y) \cdot 1 = 0 + (- 18 = 0,) \cdot 3 x + (- 18 = 0,) (- 8 y) + (- 18 = 0,) \cdot 1 = 0

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

3 \cdot 3 xx - 3 \cdot 8 x y + 3 \cdot 1 \cdot x = 0 - 8 \cdot 3 x y + 8 \cdot 8 yy - 8 \cdot 1 \cdot y = 0 - 18 = 0, 3 x + 18 = 0, 8 y - 18 = 0, 1 = 0

Expand

3 \cdot 3 xx - 3 \cdot 8 x y + 3 \cdot 1 \cdot x : 9 x^{2} - 24 x y + 3 x

9 x^{2} - 24 x y + 3 x = 0

\frac{\partial}{\partial x} ((x - 1)^{2}) + (y + 2)^{2}

(- 2 + 6 i)^{4}

(1 - \frac{( x ^{2} )}{2}) \cdot (x - \frac{( x ^{3} )}{6})

l im x \Rightarrow 0 - (cos (2 x) + x^{2}) cot (3 x)

\frac{5 x ^{2} + 9 x + 3}{x ( x + 1 ) ^{2}}

What is expand (3x-8y-18=0,)(3x-8y+1=0) ?
The solution to expand (3x-8y-18=0,)(3x-8y+1=0) is 9x^2-24xy+3x=0