What is expand tan^2(a)(2cos^2(a)+sin^2(a-1)) ?

The solution to expand tan^2(a)(2cos^2(a)+sin^2(a-1)) is tan^2(a)sin^2(a-1)+2sin^2(a)

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expand tan^2(a)(2cos^2(a)+sin^2(a-1))

expand

tan^{2} (a) (2 cos^{2} (a) + sin^{2} (a - 1))

tan^{2} (a) sin^{2} (a - 1) + 2 sin^{2} (a)

Solution steps

tan^{2} (a) (2 cos^{2} (a) + sin^{2} (a - 1))

Apply the distributive law:

a (b + c) = ab + a c

tan^{2} (a) (2 cos^{2} (a) + sin^{2} (a - 1)) = tan^{2} (a) \cdot 2 cos^{2} (a) + tan^{2} (a) sin^{2} (a - 1)

= tan^{2} (a) \cdot 2 cos^{2} (a) + tan^{2} (a) sin^{2} (a - 1)

Simplify

tan^{2} (a) \cdot 2 cos^{2} (a) + tan^{2} (a) sin^{2} (a - 1) : tan^{2} (a) sin^{2} (a - 1) + 2 sin^{2} (a)

= tan^{2} (a) sin^{2} (a - 1) + 2 sin^{2} (a)

A (3, - 3) y B (0, 3)

15 (\frac{2}{5} + 3 x)

\frac{4 ( sin ( 2 πn ) - πn cos ( 2 πn ) )}{n ^{2}}

x (x^{4} e^{4 x} + 5)

What is expand tan^2(a)(2cos^2(a)+sin^2(a-1)) ?
The solution to expand tan^2(a)(2cos^2(a)+sin^2(a-1)) is tan^2(a)sin^2(a-1)+2sin^2(a)