What is expand (x+5)(x+3)(x-4)''' ?

The solution to expand (x+5)(x+3)(x-4)''' is x^2(x-4)'''+8x(x-4)'''+15(x-4)'''

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expand (x+5)(x+3)(x-4)'''

expand

(x + 5) (x + 3) (x - 4)^{'''}

x^{2} (x - 4)''' + 8 x (x - 4)''' + 15 (x - 4)'''

Solution steps

(x + 5) (x + 3) (x - 4)^{'''}

Expand

(x + 5) (x + 3) : x^{2} + 8 x + 15

= (x - 4)^{'''} (x^{2} + 8 x + 15)

Expand

(x - 4)^{'''} (x^{2} + 8 x + 15) : x^{2} (x - 4)^{'''} + 8 x (x - 4)^{'''} + 15 (x - 4)^{'''}

= x^{2} (x - 4)^{'''} + 8 x (x - 4)^{'''} + 15 (x - 4)^{'''}

x d y + (2 y - 10 x^{2}) d x

(x - 4) (x - 7)^{'}

d x (x^{2} + y^{2} - 5 = 0)

(b) (a b - b a)

\frac{x ^{2} + 2 x + 9}{( x ^{2} + 1 ) ( x + 4 )}

What is expand (x+5)(x+3)(x-4)''' ?
The solution to expand (x+5)(x+3)(x-4)''' is x^2(x-4)'''+8x(x-4)'''+15(x-4)'''