What is expand-5[(x^3+1)(x+4)] ?

The solution to expand-5[(x^3+1)(x+4)] is -5x^4-20x^3-5x-20

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expand-5[(x^3+1)(x+4)]

expand

- 5 [(x^{3} + 1) (x + 4)]

- 5 x^{4} - 20 x^{3} - 5 x - 20

Solution steps

- 5 ((x^{3} + 1) (x + 4))

Remove parentheses:

(a) = a

= - 5 (x^{3} + 1) (x + 4)

Expand

(x^{3} + 1) (x + 4) : x^{4} + 4 x^{3} + x + 4

= - 5 (x^{4} + 4 x^{3} + x + 4)

Expand

- 5 (x^{4} + 4 x^{3} + x + 4) : - 5 x^{4} - 20 x^{3} - 5 x - 20

= - 5 x^{4} - 20 x^{3} - 5 x - 20

(x - 2 + 2)^{2}

cos (2) (π - θ)

x^{\frac{1}{3}} (4 x - 4)

\frac{27 + 3 s ^{3} + 2 s ^{2}}{s ^{2} ( s ^{2} + 9 )}

\frac{x ( x ^{2} + 1 )}{( x + 1 ) ( x - 1 )}

What is expand-5[(x^3+1)(x+4)] ?
The solution to expand-5[(x^3+1)(x+4)] is -5x^4-20x^3-5x-20