What is expand 1/3 (t-6)-1/3 e^{-3(t-6)} ?

The solution to expand 1/3 (t-6)-1/3 e^{-3(t-6)} is t/3-(e^{-3t+18})/3-2

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expand 1/3 (t-6)-1/3 e^{-3(t-6)}

expand

\frac{1}{3} (t - 6) - \frac{1}{3} e^{- 3 (t - 6)}

\frac{t}{3} - \frac{e ^{- 3 t + 18}}{3} - 2

Solution steps

\frac{1}{3} (t - 6) - \frac{1}{3} e^{- 3 (t - 6)}

Expand

\frac{1}{3} (t - 6) : \frac{t}{3} - 2

= \frac{t}{3} - 2 - \frac{1}{3} e^{- 3 (t - 6)}

Simplify

\frac{t}{3} - 2 - \frac{1}{3} e^{- 3 (t - 6)} : \frac{t}{3} - \frac{e ^{- 3 t + 18}}{3} - 2

= \frac{t}{3} - \frac{e ^{- 3 t + 18}}{3} - 2

(\frac{x}{2})^{2}

(v^{\frac{1}{2}} + 2)^{4}

\frac{x - 4}{( x + 5 ) ( x - 1 )}

d x (6 x + 9) e^{3} x^{6} - 8 x + 5

\frac{3}{( s ^{2} + 4 ) ( s ^{2} + 9 )}

What is expand 1/3 (t-6)-1/3 e^{-3(t-6)} ?
The solution to expand 1/3 (t-6)-1/3 e^{-3(t-6)} is t/3-(e^{-3t+18})/3-2