What is (\partial)/(\partial x)((z)(yz-z^2+xny)) ?

The answer to (\partial)/(\partial x)((z)(yz-z^2+xny)) is nzy

Popular >

(\partial)/(\partial x)((z)(yz-z^2+xny))

\frac{\partial}{\partial x} ((z) (yz - z^{2} + x n y))

n zy

Solution steps

\frac{\partial}{\partial x} ((z) (yz - z^{2} + x n y))

Treat

n, z, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= z \frac{\partial}{\partial x} (yz - z^{2} + x n y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= z (\frac{\partial}{\partial x} (yz) - \frac{\partial}{\partial x} (z^{2}) + \frac{\partial}{\partial x} (x n y))

\frac{\partial}{\partial x} (yz) = 0

\frac{\partial}{\partial x} (z^{2}) = 0

\frac{\partial}{\partial x} (x n y) = y n

= z (0 - 0 + y n)

Simplify

= n zy

\frac{6 x ^{2} - 24 x}{( x - 2 ) ^{2}}

\frac{100 ( 7 + 7 )}{3}

cos (2 (t - π))

(8 sin (x) + 8 cos (x))^{2}

\frac{d}{d t} ((x) (arctan (\frac{3}{x}) + arctan (\frac{9}{x})))

What is (\partial)/(\partial x)((z)(yz-z^2+xny)) ?
The answer to (\partial)/(\partial x)((z)(yz-z^2+xny)) is nzy