What is expand e^{3t}(9-4t+10sin(t/2)) ?

The solution to expand e^{3t}(9-4t+10sin(t/2)) is 9e^{3t}-4e^{3t}t+10e^{3t}sin(t/2)

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expand e^{3t}(9-4t+10sin(t/2))

expand

e^{3 t} (9 - 4 t + 10 sin (\frac{t}{2}))

9 e^{3 t} - 4 e^{3 t} t + 10 e^{3 t} sin (\frac{t}{2})

Solution steps

e^{3 t} (9 - 4 t + 10 sin (\frac{t}{2}))

Distribute parentheses

= e^{3 t} \cdot 9 + e^{3 t} (- 4 t) + e^{3 t} \cdot 10 sin (\frac{t}{2})

Apply minus-plus rules

+ (- a) = - a

= 9 e^{3 t} - 4 e^{3 t} t + 10 e^{3 t} sin (\frac{t}{2})

x^{\frac{7}{2}} - 8 x^{3} (- 3 + x)

(e^{4 x} - 2 e^{x})^{2}

\frac{1}{( 2 - 3 x ) ^{2}}

\frac{11 s ^{2} + 172 s + 700}{( s + 2 ) ( s ^{2} + 12 s + 100 )}

(3 x^{2} + 18 x + 27) (x + 3)^{\frac{1}{5}}

What is expand e^{3t}(9-4t+10sin(t/2)) ?
The solution to expand e^{3t}(9-4t+10sin(t/2)) is 9e^{3t}-4e^{3t}t+10e^{3t}sin(t/2)