What is expand e^{2t}t^{1/5}+tu(t-4) ?

The solution to expand e^{2t}t^{1/5}+tu(t-4) is e^{2t}t^{1/5}+t^2u-4tu

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand e^{2t}t^{1/5}+tu(t-4)

expand

e^{2 t} t^{\frac{1}{5}} + t u (t - 4)

e^{2 t} t^{\frac{1}{5}} + t^{2} u - 4 t u

Solution steps

e^{2 t} t^{\frac{1}{5}} + t u (t - 4)

Expand

t u (t - 4) : t^{2} u - 4 t u

= e^{2 t} t^{\frac{1}{5}} + t^{2} u - 4 t u

cot (a) (sin (a) + tan (a))

\frac{2 ( s ^{2} + 1 )}{s ^{2} ( s ^{2} + 5 )}

5^{4}

\frac{5 ( 5 t ^{2} - 1 ) ^{4} ( 100 t - 5 t ^{2} - 1 )}{( 10 - t ) ^{6}}

sin (t) - sin (t) (u) (t - 2 π)

What is expand e^{2t}t^{1/5}+tu(t-4) ?
The solution to expand e^{2t}t^{1/5}+tu(t-4) is e^{2t}t^{1/5}+t^2u-4tu