What is expand (-1)/3 3^2+2/3 3+8/3 ?

The solution to expand (-1)/3 3^2+2/3 3+8/3 is 5/3

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expand (-1)/3 3^2+2/3 3+8/3

expand

\frac{- 1}{3} 3^{2} + \frac{2}{3} 3 + \frac{8}{3}

\frac{5}{3}

Decimal Notation

1.66666 \dots

Solution steps

\frac{- 1}{3} \cdot 3^{2} + \frac{2}{3} \cdot 3 + \frac{8}{3}

\frac{- 1}{3} \cdot 3^{2} = - 3

= - 3 + 3 \cdot \frac{2}{3} + \frac{8}{3}

\frac{2}{3} \cdot 3 = 2

= - 3 + 2 + \frac{8}{3}

Add/Subtract the numbers:

- 3 + 2 = - 1

= \frac{8}{3} - 1

Convert element to fraction:

1 = \frac{1 \cdot 3}{3}

= - \frac{1 \cdot 3}{3} + \frac{8}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 1 \cdot 3 + 8}{3}

- 1 \cdot 3 + 8 = 5

= \frac{5}{3}

(e^{- x} + 1)^{2}

x^{\frac{1}{3}} \cdot (x - 2)^{2}

(x - y) d x + y^{2} d y

\frac{csc ( a ) ( tan ( a ) - sin ( a ) )}{1 - sec ( a )}

\frac{x ( x + 4 )}{2}

What is expand (-1)/3 3^2+2/3 3+8/3 ?
The solution to expand (-1)/3 3^2+2/3 3+8/3 is 5/3