What is expand 4(-4e^{x^2-y^2}x^2y-2e^{x^2-y^2}y) ?

The solution to expand 4(-4e^{x^2-y^2}x^2y-2e^{x^2-y^2}y) is -16e^{x^2-y^2}x^2y-8e^{x^2-y^2}y

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expand 4(-4e^{x^2-y^2}x^2y-2e^{x^2-y^2}y)

expand

4 (- 4 e^{x^{2} - y^{2}} x^{2} y - 2 e^{x^{2} - y^{2}} y)

- 16 e^{x^{2} - y^{2}} x^{2} y - 8 e^{x^{2} - y^{2}} y

Solution steps

4 (- 4 e^{x^{2} - y^{2}} x^{2} y - 2 e^{x^{2} - y^{2}} y)

Apply the distributive law:

a (b - c) = ab - a c

a = 4, b = - 4 e^{x^{2} - y^{2}} x^{2} y, c = 2 e^{x^{2} - y^{2}} y

= 4 (- 4 e^{x^{2} - y^{2}} x^{2} y) - 4 \cdot 2 e^{x^{2} - y^{2}} y

Apply minus-plus rules

+ (- a) = - a

= - 4 \cdot 4 e^{x^{2} - y^{2}} x^{2} y - 4 \cdot 2 e^{x^{2} - y^{2}} y

Simplify

- 4 \cdot 4 e^{x^{2} - y^{2}} x^{2} y - 4 \cdot 2 e^{x^{2} - y^{2}} y : - 16 e^{x^{2} - y^{2}} x^{2} y - 8 e^{x^{2} - y^{2}} y

= - 16 e^{x^{2} - y^{2}} x^{2} y - 8 e^{x^{2} - y^{2}} y

(x + x^{2} + 1)^{10}

(- 5 x + 5 y = - 2, 5) (8 x - 3 y = 30)

(8, 6) (- 9, - 9) (x, - 8)

(r cos (θ) - 1)^{2}

\frac{1}{( s - 2 i ) ^{2}} + \frac{1}{( s + 2 i ) ^{2}}

What is expand 4(-4e^{x^2-y^2}x^2y-2e^{x^2-y^2}y) ?
The solution to expand 4(-4e^{x^2-y^2}x^2y-2e^{x^2-y^2}y) is -16e^{x^2-y^2}x^2y-8e^{x^2-y^2}y