What is 1/((s-2i)^2)+1/((s+2i)^2) ?

The solution to 1/((s-2i)^2)+1/((s+2i)^2) is (2s^2-8)/(s^4+8s^2+16)

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simplify 1/((s-2i)^2)+1/((s+2i)^2)

simplify

\frac{1}{( s - 2 i ) ^{2}} + \frac{1}{( s + 2 i ) ^{2}}

\frac{2 s ^{2} - 8}{s ^{4} + 8 s ^{2} + 16}

Solution steps

\frac{1}{( s - 2 i ) ^{2}} + \frac{1}{( s + 2 i ) ^{2}}

\frac{1}{( s - 2 i ) ^{2}} = \frac{s ^{2} - 4 + 4 s i}{s ^{4} + 8 s ^{2} + 16}

\frac{1}{( s + 2 i ) ^{2}} = \frac{s ^{2} - 4 - 4 s i}{s ^{4} + 8 s ^{2} + 16}

= \frac{s ^{2} - 4 + 4 s i}{s ^{4} + 8 s ^{2} + 16} + \frac{s ^{2} - 4 - 4 s i}{s ^{4} + 8 s ^{2} + 16}

Join

\frac{s ^{2} - 4 + 4 s i}{s ^{4} + 8 s ^{2} + 16} + \frac{s ^{2} - 4 - 4 s i}{s ^{4} + 8 s ^{2} + 16} : \frac{2 s ^{2} - 8}{s ^{4} + 8 s ^{2} + 16}

= \frac{2 s ^{2} - 8}{s ^{4} + 8 s ^{2} + 16}

224 (s + s^{'})^{9}

x + 2 (3 x - 2)

(- 9, 6) y (- 7, - 8)

(9.3 + 2.1 i)^{4}

(2 x^{\frac{2}{3}} y + x y^{\frac{3}{4}})^{2}

What is 1/((s-2i)^2)+1/((s+2i)^2) ?
The solution to 1/((s-2i)^2)+1/((s+2i)^2) is (2s^2-8)/(s^4+8s^2+16)