What is expand ((18n-7)^2)/(441) ?

The solution to expand ((18n-7)^2)/(441) is (36n^2}{49}-\frac{4n)/7+1/9

Popular >

expand ((18n-7)^2)/(441)

expand

\frac{( 18 n - 7 ) ^{2}}{441}

\frac{36 n ^{2}}{49} - \frac{4 n}{7} + \frac{1}{9}

Solution steps

\frac{( 18 n - 7 ) ^{2}}{441}

(18 n - 7)^{2} = 324 n^{2} - 252 n + 49

= \frac{324 n ^{2} - 252 n + 49}{441}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{324 n ^{2} - 252 n + 49}{441} = \frac{324 n ^{2}}{441} - \frac{252 n}{441} + \frac{49}{441}

= \frac{324 n ^{2}}{441} - \frac{252 n}{441} + \frac{49}{441}

Cancel

\frac{324 n ^{2}}{441} : \frac{36 n ^{2}}{49}

= \frac{36 n ^{2}}{49} - \frac{252 n}{441} + \frac{49}{441}

Cancel

\frac{252 n}{441} : \frac{4 n}{7}

= \frac{36 n ^{2}}{49} - \frac{4 n}{7} + \frac{49}{441}

Cancel

\frac{49}{441} : \frac{1}{9}

= \frac{36 n ^{2}}{49} - \frac{4 n}{7} + \frac{1}{9}

52 (33 + 45)

\frac{3 x ^{2} - 10 x + 6}{2 - 3 x + 5 ( x ^{2} - 2 ) ^{\frac{3}{2}}}

(sec (B) - tan (B))^{2}

\frac{e ^{- 5 s} ( 2 s + 3 )}{s ( s ^{2} + 2 s + 5 )}

\frac{d}{d y} ((x (y)) (\frac{y ^{4}}{4} + \frac{1}{8 y ^{2}}))

What is expand ((18n-7)^2)/(441) ?
The solution to expand ((18n-7)^2)/(441) is (36n^2}{49}-\frac{4n)/7+1/9