What is 6((4x^3)/3-2x^2+x) ?

The solution to 6((4x^3)/3-2x^2+x) is 8x^3-12x^2+6x

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simplify 6((4x^3)/3-2x^2+x)

simplify

6 (\frac{4 x ^{3}}{3} - 2 x^{2} + x)

8 x^{3} - 12 x^{2} + 6 x

Solution steps

6 (\frac{4 x ^{3}}{3} - 2 x^{2} + x)

Join

\frac{4 x ^{3}}{3} - 2 x^{2} + x : \frac{4 x ^{3} - 6 x ^{2} + x \cdot 3}{3}

= 6 \cdot \frac{4 x ^{3} - 6 x ^{2} + x \cdot 3}{3}

= 6 \cdot \frac{4 x ^{3} - 6 x ^{2} + 3 x}{3}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{6 ( 4 x ^{3} - 6 x ^{2} + 3 x )}{3}

Divide the numbers:

\frac{6}{3} = 2

= 2 (4 x^{3} - 6 x^{2} + 3 x)

Expand

2 (4 x^{3} - 6 x^{2} + 3 x) : 8 x^{3} - 12 x^{2} + 6 x

= 8 x^{3} - 12 x^{2} + 6 x

\frac{( 4 x - 1 ) ^{2}}{16}

C (- 3, - 5)

(2 + x 5)^{2}

(3 x + 7)^{2}

(2 + x - 2)^{2}

What is 6((4x^3)/3-2x^2+x) ?
The solution to 6((4x^3)/3-2x^2+x) is 8x^3-12x^2+6x