What is expand ((x+2)(x+1))/((x-1)(x-3)) ?

The solution to expand ((x+2)(x+1))/((x-1)(x-3)) is (x^2+3x+2)/(x^2-4x+3)

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expand ((x+2)(x+1))/((x-1)(x-3))

expand

\frac{( x + 2 ) ( x + 1 )}{( x - 1 ) ( x - 3 )}

\frac{x ^{2} + 3 x + 2}{x ^{2} - 4 x + 3}

Solution steps

\frac{( x + 2 ) ( x + 1 )}{( x - 1 ) ( x - 3 )}

Expand

(x - 1) (x - 3) : x^{2} - 4 x + 3

= \frac{( x + 2 ) ( x + 1 )}{x ^{2} - 4 x + 3}

Expand

(x + 2) (x + 1) : x^{2} + 3 x + 2

= \frac{x ^{2} + 3 x + 2}{x ^{2} - 4 x + 3}

\frac{x - 5}{( x + 1 ) ( x - 1 )}

\frac{1}{( 1 - x ) ( 1 + x )}

(x + y i)^{8}

(2 x + 1 - 3)^{2}

\frac{x ^{2} + 1}{( x + 1 ) ( x ^{2} + 4 )}

What is expand ((x+2)(x+1))/((x-1)(x-3)) ?
The solution to expand ((x+2)(x+1))/((x-1)(x-3)) is (x^2+3x+2)/(x^2-4x+3)