What is expand (9x^5-27x^4-450x^2-12x+6)/(3x-15) ?

The solution to expand (9x^5-27x^4-450x^2-12x+6)/(3x-15) is (3x^5-9x^4-150x^2-4x+2)/(x-5)

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expand (9x^5-27x^4-450x^2-12x+6)/(3x-15)

expand

\frac{9 x ^{5} - 27 x ^{4} - 450 x ^{2} - 12 x + 6}{3 x - 15}

\frac{3 x ^{5} - 9 x ^{4} - 150 x ^{2} - 4 x + 2}{x - 5}

Solution steps

\frac{9 x ^{5} - 27 x ^{4} - 450 x ^{2} - 12 x + 6}{3 x - 15}

Factor

9 x^{5} - 27 x^{4} - 450 x^{2} - 12 x + 6 : 3 (3 x^{5} - 9 x^{4} - 150 x^{2} - 4 x + 2)

= \frac{3 ( 3 x ^{5} - 9 x ^{4} - 150 x ^{2} - 4 x + 2 )}{3 x - 15}

Factor

3 x - 15 : 3 (x - 5)

= \frac{3 ( 3 x ^{5} - 9 x ^{4} - 150 x ^{2} - 4 x + 2 )}{3 ( x - 5 )}

Divide the numbers:

\frac{3}{3} = 1

= \frac{3 x ^{5} - 9 x ^{4} - 150 x ^{2} - 4 x + 2}{( x - 5 )}

Remove parentheses:

(a) = a

= \frac{3 x ^{5} - 9 x ^{4} - 150 x ^{2} - 4 x + 2}{x - 5}

\frac{5 x - 8}{( x + 1 ) ( x - 1 )}

(x - \frac{y}{y ^{'} ( x )})^{2} + (y - x y^{'} (x))^{2}

\frac{1}{s ( t s + 1 )}

\frac{x}{( x + B ) ( x - A )}

(x - 3) (x - \frac{5}{2})

What is expand (9x^5-27x^4-450x^2-12x+6)/(3x-15) ?
The solution to expand (9x^5-27x^4-450x^2-12x+6)/(3x-15) is (3x^5-9x^4-150x^2-4x+2)/(x-5)