What is 3(-(y^3)/3-y+4)(((-y^3-3y+12)^2)/9-2) ?

The solution to 3(-(y^3)/3-y+4)(((-y^3-3y+12)^2)/9-2) is (-y^3-3y+12)(((-y^3-3y+12)^2)/9-2)

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simplify 3(-(y^3)/3-y+4)(((-y^3-3y+12)^2)/9-2)

simplify

3 (- \frac{y ^{3}}{3} - y + 4) (\frac{( - y ^{3} - 3 y + 12 ) ^{2}}{9} - 2)

(- y^{3} - 3 y + 12) (\frac{( - y ^{3} - 3 y + 12 ) ^{2}}{9} - 2)

Solution steps

3 (- \frac{y ^{3}}{3} - y + 4) (\frac{( - y ^{3} - 3 y + 12 ) ^{2}}{9} - 2)

Simplify

- \frac{y ^{3}}{3} - y + 4 : \frac{- y ^{3} - 3 y + 12}{3}

= 3 \cdot \frac{- y ^{3} - 3 y + 12}{3} (\frac{( - y ^{3} - 3 y + 12 ) ^{2}}{9} - 2)

Cross-cancel common factor:

3

= (- y^{3} - 3 y + 12) (\frac{( - y ^{3} - 3 y + 12 ) ^{2}}{9} - 2)

- x (2 x + y = 7)

(cos (x) + 2)^{2}

\frac{( n + 2 ) ^{2}}{n + 8}

(3 z - 4 i)^{2}

\frac{2 x ^{3} - 4 x ^{2} - 15 x + 8}{( x - 1 ) ^{2}}

What is 3(-(y^3)/3-y+4)(((-y^3-3y+12)^2)/9-2) ?
The solution to 3(-(y^3)/3-y+4)(((-y^3-3y+12)^2)/9-2) is (-y^3-3y+12)(((-y^3-3y+12)^2)/9-2)