What is expand (2x^3-4x^2-15x+8)/((x-1)^2) ?

The solution to expand (2x^3-4x^2-15x+8)/((x-1)^2) is (2x^3-4x^2-15x+8)/(x^2-2x+1)

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expand (2x^3-4x^2-15x+8)/((x-1)^2)

expand

\frac{2 x ^{3} - 4 x ^{2} - 15 x + 8}{( x - 1 ) ^{2}}

\frac{2 x ^{3} - 4 x ^{2} - 15 x + 8}{x ^{2} - 2 x + 1}

Solution steps

\frac{2 x ^{3} - 4 x ^{2} - 15 x + 8}{( x - 1 ) ^{2}}

(x - 1)^{2} = x^{2} - 2 x + 1

= \frac{2 x ^{3} - 4 x ^{2} - 15 x + 8}{x ^{2} - 2 x + 1}

(\frac{( x ^{2} - 4 )}{x} - k)^{2}

\frac{4 - s}{( s + 2 j ) ( s - 2 j ) ( s + 1 )}

\frac{\frac{d}{d x} ( 2 x ^{2} ) - 13 x + 22}{( x - 2 ) ^{2}}

d (1 + x e^{y})

(sin (2 t) + cos (2 t))^{2}

What is expand (2x^3-4x^2-15x+8)/((x-1)^2) ?
The solution to expand (2x^3-4x^2-15x+8)/((x-1)^2) is (2x^3-4x^2-15x+8)/(x^2-2x+1)