What is expand (x^{2/3}-\sqrt[3]{x})^3 ?

The solution to expand (x^{2/3}-\sqrt[3]{x})^3 is x^2-3x^{5/3}+3x^{4/3}-x

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expand (x^{2/3}-\sqrt[3]{x})^3

expand

x^{2} - 3 x^{\frac{5}{3}} + 3 x^{\frac{4}{3}} - x

Solution steps

Apply Perfect Cube Formula:

(a - b)^{3} = a^{3} - 3 a^{2} b + 3 a b^{2} - b^{3}

(x^{\frac{2}{3}})^{3} = x^{2}

= x^{2} - 3 x^{\frac{5}{3}} + 3 x^{\frac{4}{3}} - x

(3 cos (θ) + 2 sin (θ))^{2}

(2 x + 1)^{2} d x

\frac{e ^{- 2 - 2} ( 3 + 2 2 )}{8}

\frac{4}{3} (15 - 6 y - 7 = - 11)

(a + b + c)^{5}

What is expand (x^{2/3}-\sqrt[3]{x})^3 ?
The solution to expand (x^{2/3}-\sqrt[3]{x})^3 is x^2-3x^{5/3}+3x^{4/3}-x