What is (\partial)/(\partial s)((w)(2(r^2+s^2))) ?

The answer to (\partial)/(\partial s)((w)(2(r^2+s^2))) is 4ws

Popular >

(\partial)/(\partial s)((w)(2(r^2+s^2)))

\frac{\partial}{\partial s} ((w) (2 (r^{2} + s^{2})))

4 w s

Solution steps

\frac{\partial}{\partial s} ((w) (2 (r^{2} + s^{2})))

Treat

w, r

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= w \cdot 2 \frac{\partial}{\partial s} (r^{2} + s^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= w \cdot 2 (\frac{\partial}{\partial s} (r^{2}) + \frac{\partial}{\partial s} (s^{2}))

\frac{\partial}{\partial s} (r^{2}) = 0

\frac{\partial}{\partial s} (s^{2}) = 2 s

= w \cdot 2 (0 + 2 s)

Simplify

= 4 w s

\frac{( e ^{(a t)} + e ^{(- a t)} ) \cdot e ^{(- s t)}}{2}

i (x - i y)^{2}

\frac{8}{( x - 1 ) ( x + 1 ) ( x + 3 )}

\frac{18 s ^{2}}{( s + 1 ) ( s + 4 )}

A (- 2, - 3) y B (2, 2)

What is (\partial)/(\partial s)((w)(2(r^2+s^2))) ?
The answer to (\partial)/(\partial s)((w)(2(r^2+s^2))) is 4ws