What is expand (2s-3)/(s(s-2)(s^2-2s+5)) ?

The solution to expand (2s-3)/(s(s-2)(s^2-2s+5)) is (2s-3)/(s^4-4s^3+9s^2-10s)

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expand (2s-3)/(s(s-2)(s^2-2s+5))

expand

\frac{2 s - 3}{s ( s - 2 ) ( s ^{2} - 2 s + 5 )}

\frac{2 s - 3}{s ^{4} - 4 s ^{3} + 9 s ^{2} - 10 s}

Solution steps

\frac{2 s - 3}{s ( s - 2 ) ( s ^{2} - 2 s + 5 )}

Expand

s (s - 2) (s^{2} - 2 s + 5) : s^{4} - 4 s^{3} + 9 s^{2} - 10 s

= \frac{2 s - 3}{s ^{4} - 4 s ^{3} + 9 s ^{2} - 10 s}

(\frac{a ^{2} \cdot a ^{9}}{a ^{5}})^{7}

(2 - \frac{1}{n})^{2}

(1 - x 3)^{2}

\frac{( x - 4 ) ^{2}}{( x - 2 )}

\frac{6 x ^{2} - 3 x + 1}{( 4 x + 1 ) ( x ^{2} + 1 )}

What is expand (2s-3)/(s(s-2)(s^2-2s+5)) ?
The solution to expand (2s-3)/(s(s-2)(s^2-2s+5)) is (2s-3)/(s^4-4s^3+9s^2-10s)