What is expand x^{2/3}(x^2-9) ?

The solution to expand x^{2/3}(x^2-9) is x^{8/3}-x^{2/3}*9

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expand x^{2/3}(x^2-9)

expand

x^{\frac{2}{3}} (x^{2} - 9)

x^{\frac{8}{3}} - x^{\frac{2}{3}} \cdot 9

Solution steps

x^{\frac{2}{3}} (x^{2} - 9)

Apply the distributive law:

a (b - c) = ab - a c

x^{\frac{2}{3}} (x^{2} - 9) = x^{\frac{2}{3}} x^{2} - x^{\frac{2}{3}} \cdot 9

= x^{\frac{2}{3}} x^{2} - x^{\frac{2}{3}} \cdot 9

Simplify

x^{\frac{2}{3}} x^{2} : x^{\frac{8}{3}}

= x^{\frac{8}{3}} - x^{\frac{2}{3}} \cdot 9

e^{x} (3 cos (3 x) + 9 sin (3 x))

s^{2} (2 + \frac{2}{s})

1 + \frac{K ( s + 1 ) ( s + 2.69 )}{s ^{3}}

\frac{1260}{( 2 x + 3 ) ^{3}}

\frac{5 n ( n + 1 )}{2}

What is expand x^{2/3}(x^2-9) ?
The solution to expand x^{2/3}(x^2-9) is x^{8/3}-x^{2/3}*9