What is expand-r^3(1+sin^2(θ)) ?

The solution to expand-r^3(1+sin^2(θ)) is -r^3-r^3sin^2(θ)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-r^3(1+sin^2(θ))

expand

- r^{3} (1 + sin^{2} (θ))

- r^{3} - r^{3} sin^{2} (θ)

Solution steps

- r^{3} (1 + sin^{2} (θ))

Apply the distributive law:

a (b + c) = ab + a c

- r^{3} (1 + sin^{2} (θ)) = - r^{3} \cdot 1 - r^{3} sin^{2} (θ)

= - r^{3} \cdot 1 - r^{3} sin^{2} (θ)

Apply rule:

a \cdot 1 = a

- r^{3} \cdot 1 = - r^{3}

= - r^{3} - r^{3} sin^{2} (θ)

x y d x + (y^{4} - 3 x^{2}) d y

a (- 1, - 3, 2) b (1, - 1, 3)

(- 3 - i)^{11}

- 2 (- x cos (x) + sin (x))

What is expand-r^3(1+sin^2(θ)) ?
The solution to expand-r^3(1+sin^2(θ)) is -r^3-r^3sin^2(θ)