What is expand (2(3x^4-1))/(x^3) ?

The solution to expand (2(3x^4-1))/(x^3) is 6x-2/(x^3)

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expand (2(3x^4-1))/(x^3)

expand

\frac{2 ( 3 x ^{4} - 1 )}{x ^{3}}

6 x - \frac{2}{x ^{3}}

Solution steps

\frac{2 ( 3 x ^{4} - 1 )}{x ^{3}}

Expand

2 (3 x^{4} - 1) : 6 x^{4} - 2

= \frac{6 x ^{4} - 2}{x ^{3}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{6 x ^{4} - 2}{x ^{3}} = \frac{6 x ^{4}}{x ^{3}} - \frac{2}{x ^{3}}

= \frac{6 x ^{4}}{x ^{3}} - \frac{2}{x ^{3}}

Cancel

\frac{6 x ^{4}}{x ^{3}} : 6 x

= 6 x - \frac{2}{x ^{3}}

(1 - cos (x)) (cos (x))

d z (3 x y^{2} - 2 x^{2} y + 5)

(4, 7) v er t i ce (4, - 5) ce n t ro (4, 2)

(\frac{x}{4} - \frac{3 y}{2}) (\frac{x}{4} + \frac{3 y}{2})

\frac{- 12 x ^{2} - 16}{( 2 x + 1 ) ^{2}}

What is expand (2(3x^4-1))/(x^3) ?
The solution to expand (2(3x^4-1))/(x^3) is 6x-2/(x^3)