What is expand (-12x^2-16)/((2x+1)^2) ?

The solution to expand (-12x^2-16)/((2x+1)^2) is (-12x^2-16)/(4x^2+4x+1)

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expand (-12x^2-16)/((2x+1)^2)

expand

\frac{- 12 x ^{2} - 16}{( 2 x + 1 ) ^{2}}

\frac{- 12 x ^{2} - 16}{4 x ^{2} + 4 x + 1}

Solution steps

\frac{- 12 x ^{2} - 16}{( 2 x + 1 ) ^{2}}

(2 x + 1)^{2} = 4 x^{2} + 4 x + 1

= \frac{- 12 x ^{2} - 16}{4 x ^{2} + 4 x + 1}

(x + Δ)^{2}

\frac{d}{d t} ((x) (x - y))

\frac{8 x d x}{( 2 x ^{2} + 5 ) ^{4}}

\frac{x ^{2} - 4 x + 10}{( x - 2 ) ^{2}}

\frac{2 x - 3}{( x - 3 ) ( x - 4 )}

What is expand (-12x^2-16)/((2x+1)^2) ?
The solution to expand (-12x^2-16)/((2x+1)^2) is (-12x^2-16)/(4x^2+4x+1)