What is expand (2x-3)/((x-3)(x-4)) ?

The solution to expand (2x-3)/((x-3)(x-4)) is (2x-3)/(x^2-7x+12)

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expand (2x-3)/((x-3)(x-4))

expand

\frac{2 x - 3}{( x - 3 ) ( x - 4 )}

\frac{2 x - 3}{x ^{2} - 7 x + 12}

Solution steps

\frac{2 x - 3}{( x - 3 ) ( x - 4 )}

Expand

(x - 3) (x - 4) : x^{2} - 7 x + 12

= \frac{2 x - 3}{x ^{2} - 7 x + 12}

(1 + y e^{x y}) d x

(x - 22)^{2}

e^{2 x} (2 cos (x) - sin (x))

\frac{3 x ( - x ^{2} - x + 2 )}{2}

(x - cos (y)) d x - sin (y) d y

What is expand (2x-3)/((x-3)(x-4)) ?
The solution to expand (2x-3)/((x-3)(x-4)) is (2x-3)/(x^2-7x+12)