What is expand (3x(-x^2-x+2))/2 ?

The solution to expand (3x(-x^2-x+2))/2 is -(3x^3)/2-(3x^2)/2+3x

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expand (3x(-x^2-x+2))/2

expand

\frac{3 x ( - x ^{2} - x + 2 )}{2}

- \frac{3 x ^{3}}{2} - \frac{3 x ^{2}}{2} + 3 x

Solution steps

\frac{3 x ( - x ^{2} - x + 2 )}{2}

Expand

3 x (- x^{2} - x + 2) : - 3 x^{3} - 3 x^{2} + 6 x

= \frac{- 3 x ^{3} - 3 x ^{2} + 6 x}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 3 x ^{3} - 3 x ^{2} + 6 x}{2} = - \frac{3 x ^{3}}{2} - \frac{3 x ^{2}}{2} + \frac{6 x}{2}

= - \frac{3 x ^{3}}{2} - \frac{3 x ^{2}}{2} + \frac{6 x}{2}

Divide the numbers:

\frac{6}{2} = 3

= - \frac{3 x ^{3}}{2} - \frac{3 x ^{2}}{2} + 3 x

(x - cos (y)) d x - sin (y) d y

(1 - tan (θ)) tan (2 θ)

- \frac{2 x ( - x ^{2} + 189 )}{( x ^{2} + 63 ) ^{3}}

(1 + x^{2}) (1 + x^{2})

(e^{\frac{x}{2}} + e^{- \frac{x}{2}})^{2}

What is expand (3x(-x^2-x+2))/2 ?
The solution to expand (3x(-x^2-x+2))/2 is -(3x^3)/2-(3x^2)/2+3x