What are the solutions to the equation -5(x+6)^2+40=0 ?

The solutions to the equation -5(x+6)^2+40=0 are x=2sqrt(2)-6,x=-2sqrt(2)-6

Find the zeros of -5(x+6)^2+40=0

The zeros of -5(x+6)^2+40=0 are x=2sqrt(2)-6,x=-2sqrt(2)-6

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- 5 (x + 6)^{2} + 40 = 0

x = 22 - 6, x = - 22 - 6

Solution steps

- 5 (x + 6)^{2} + 40 = 0

Move

40

to the right side

- 5 (x + 6)^{2} = - 40

Divide both sides by

- 5

(x + 6)^{2} = 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 6 = 8 : x = 22 - 6

Solve

x + 6 = - 8 : x = - 22 - 6

The solutions to the quadratic equation are:

x = 22 - 6, x = - 22 - 6

3 r + 2 \geq 18

4 x^{2} = - 13 x - 3

\frac{1}{- 4 i}

8^{\frac{7}{3}}

x - 2 = 4 - x

What are the solutions to the equation -5(x+6)^2+40=0 ?
The solutions to the equation -5(x+6)^2+40=0 are x=2sqrt(2)-6,x=-2sqrt(2)-6
Find the zeros of -5(x+6)^2+40=0
The zeros of -5(x+6)^2+40=0 are x=2sqrt(2)-6,x=-2sqrt(2)-6