What is expand log_{6}(x-2)(x+3) ?

The solution to expand log_{6}(x-2)(x+3) is xlog_{6}(x-2)+3log_{6}(x-2)

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expand log_{6}(x-2)(x+3)

expand

lo g_{6} (x - 2) (x + 3)

x lo g_{6} (x - 2) + 3 lo g_{6} (x - 2)

Solution steps

lo g_{6} (x - 2) (x + 3)

Apply the distributive law:

a (b + c) = ab + a c

lo g_{6} (x - 2) (x + 3) = lo g_{6} (x - 2) x + lo g_{6} (x - 2) \cdot 3

= lo g_{6} (x - 2) x + lo g_{6} (x - 2) \cdot 3

= x lo g_{6} (x - 2) + 3 lo g_{6} (x - 2)

A (4, - 1) y B (8, 0)

(x + 1 + i) (x + 1 - i)

\frac{2 ( x - 7 )}{7 ( x + 3 )}

(2 i + 3)^{4} + (2 i - 3)^{4}

\frac{( \frac{x}{y} ) ^{\frac{1}{4}}}{( \frac{y}{x} ) ^{\frac{3}{4}}}

What is expand log_{6}(x-2)(x+3) ?
The solution to expand log_{6}(x-2)(x+3) is xlog_{6}(x-2)+3log_{6}(x-2)