What is expand (x^2+1)(x-3) ?

The solution to expand (x^2+1)(x-3) is x(x^2+1)-3(x^2+1)

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expand (x^2+1)(x-3)

expand

(x^{2} + 1)^{\circ} (x - 3)

x (x^{2} + 1)^{\circ} - 3 (x^{2} + 1)^{\circ}

Solution steps

(x^{2} + 1)^{\circ} (x - 3)

= (x - 3) (x^{2} + 1)^{\circ}

Apply the distributive law:

a (b - c) = ab - a c

a = (x^{2} + 1)^{\circ}, b = x, c = 3

= (x^{2} + 1)^{\circ} x - (x^{2} + 1)^{\circ} \cdot 3

= x (x^{2} + 1)^{\circ} - 3 (x^{2} + 1)^{\circ}

lo g_{6} (x) (x - 1)^{2}

1 - (sin (A) + cos (A)) 2

(2 - 3 x) (x - 1)^{2} (x - 1 + 3) (x - 1 - 3)

x (x^{2} + 1)

(2 x + 1)^{2} (4 x)

What is expand (x^2+1)(x-3) ?
The solution to expand (x^2+1)(x-3) is x(x^2+1)-3(x^2+1)