What is expand (3x^2-2x-3)/((x^2+1)^2) ?

The solution to expand (3x^2-2x-3)/((x^2+1)^2) is (3x^2-2x-3)/(x^4+2x^2+1)

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expand (3x^2-2x-3)/((x^2+1)^2)

expand

\frac{3 x ^{2} - 2 x - 3}{( x ^{2} + 1 ) ^{2}}

\frac{3 x ^{2} - 2 x - 3}{x ^{4} + 2 x ^{2} + 1}

Solution steps

\frac{3 x ^{2} - 2 x - 3}{( x ^{2} + 1 ) ^{2}}

(x^{2} + 1)^{2} = x^{4} + 2 x^{2} + 1

= \frac{3 x ^{2} - 2 x - 3}{x ^{4} + 2 x ^{2} + 1}

8000 (4 \cdot 2^{\frac{2}{3}} - 1)

lo g_{10} (t^{9})

\frac{2 y - 6}{5 ( y ^{2} - 6 y ) ^{\frac{4}{5}}}

10 (lo g_{10} (141) + 12)

cot (x) (\frac{1}{3 cos ( x )} + tan (x))

What is expand (3x^2-2x-3)/((x^2+1)^2) ?
The solution to expand (3x^2-2x-3)/((x^2+1)^2) is (3x^2-2x-3)/(x^4+2x^2+1)