What are the solutions to the equation 1+4x^2=0 ?

The solutions to the equation 1+4x^2=0 are x= 1/2 i,x=-1/2 i

Find the zeros of 1+4x^2=0

The zeros of 1+4x^2=0 are x= 1/2 i,x=-1/2 i

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1 + 4 x^{2} = 0

x = \frac{1}{2} i, x = - \frac{1}{2} i

Solution steps

1 + 4 x^{2} = 0

Move

1

to the right side

4 x^{2} = - 1

Divide both sides by

4

x^{2} = - \frac{1}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{4}, x = - - \frac{1}{4}

- \frac{1}{4} = \frac{1}{2} i

- - \frac{1}{4} = - \frac{1}{2} i

x = \frac{1}{2} i, x = - \frac{1}{2} i

8 y^{2} + 6 y - 9

z^{2} + 2 z - 4 = 0

5 c^{2} + 7 c + 1 = 2 c

q^{2} + 34 = 35

\frac{2}{10} - \frac{3}{10}

What are the solutions to the equation 1+4x^2=0 ?
The solutions to the equation 1+4x^2=0 are x= 1/2 i,x=-1/2 i
Find the zeros of 1+4x^2=0
The zeros of 1+4x^2=0 are x= 1/2 i,x=-1/2 i