What is expand (-1-2i)^2 ?

The solution to expand (-1-2i)^2 is -3+4i

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expand (-1-2i)^2

expand

(- 1 - 2 i)^{2}

- 3 + 4 i

Solution steps

(- 1 - 2 i)^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(- 1 - 2 i)^{2} = (- 1)^{2} - 2 (- 1) \cdot 2 i + (2 i)^{2}

= (- 1)^{2} - 2 (- 1) \cdot 2 i + (2 i)^{2}

Simplify

(- 1)^{2} - 2 (- 1) \cdot 2 i + (2 i)^{2} : 4 i - 3

= 4 i - 3

Rewrite in standard complex form:

- 3 + 4 i

= - 3 + 4 i

f (x, y) (x^{2} - 3 x y + x - y^{2} + 4) - λ (x + y - 2)

(e^{t} - t)^{2}

2 (2^{\frac{n}{2}} - 1)

(1 - 2 z i)^{2}

e^{2 t} \cdot t^{2} \cdot U (t - 3)