What is expand (2(j+k+5))/(9(3f+3k+15)) ?

The solution to expand (2(j+k+5))/(9(3f+3k+15)) is (2j+2k+10)/(27f+27k+135)

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expand (2(j+k+5))/(9(3f+3k+15))

expand

\frac{2 ( j + k + 5 )}{9 ( 3 f + 3 k + 15 )}

\frac{2 j + 2 k + 10}{27 f + 27 k + 135}

Solution steps

\frac{2 ( j + k + 5 )}{9 ( 3 f + 3 k + 15 )}

Expand

9 (3 f + 3 k + 15) : 27 f + 27 k + 135

= \frac{2 ( j + k + 5 )}{27 f + 27 k + 135}

Expand

2 (j + k + 5) : 2 j + 2 k + 10

= \frac{2 j + 2 k + 10}{27 f + 27 k + 135}

\frac{0.5}{( 110 s + 1 ) ^{2}}

\frac{1}{8} (ln (5) - \frac{5}{8})

x^{12} (2 x^{2} + 6 x - 8)^{2}

(3 + e^{- x})^{2}

(\frac{6}{100}) + 1.61 (\frac{9.5}{100} - \frac{6}{100}) + 1.5

What is expand (2(j+k+5))/(9(3f+3k+15)) ?
The solution to expand (2(j+k+5))/(9(3f+3k+15)) is (2j+2k+10)/(27f+27k+135)