What is expand (e^{-2s}+1)/((s-2)(s-1)) ?

The solution to expand (e^{-2s}+1)/((s-2)(s-1)) is (e^{-2s}+1)/(s^2-3s+2)

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expand (e^{-2s}+1)/((s-2)(s-1))

expand

\frac{e ^{- 2 s} + 1}{( s - 2 ) ( s - 1 )}

\frac{e ^{- 2 s} + 1}{s ^{2} - 3 s + 2}

Solution steps

\frac{e ^{- 2 s} + 1}{( s - 2 ) ( s - 1 )}

Expand

(s - 2) (s - 1) : s^{2} - 3 s + 2

= \frac{e ^{- 2 s} + 1}{s ^{2} - 3 s + 2}

(1 - sec (2 x))^{2}

(3 a + b) (3 a - b)

3 r^{4 (5 r^{2} - r + 4)}

\frac{e ^{3 x - 1} ( 3 x ^{2} + 7 x - 3 )}{2 x ^{2} ( x + 3 ) ^{2}}

12 x^{2.5} (2 x^{3.5} \times 3 x^{2})

What is expand (e^{-2s}+1)/((s-2)(s-1)) ?
The solution to expand (e^{-2s}+1)/((s-2)(s-1)) is (e^{-2s}+1)/(s^2-3s+2)