What is the d/(dy)((x)(x^3+8x-5)) ?

The d/(dy)((x)(x^3+8x-5)) is 4y^3+16y-5

What is the first d/(dy)((x)(x^3+8x-5)) ?

The first d/(dy)((x)(x^3+8x-5)) is 4y^3+16y-5

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\frac{d}{d y} ((y) (y^{3} + 8 y - 5))

4 y^{3} + 16 y - 5

Solution steps

\frac{d}{d y} ((y) (y^{3} + 8 y - 5))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = y, g = y^{3} + 8 y - 5

= \frac{d y}{d y} (y^{3} + 8 y - 5) + \frac{d}{d y} (y^{3} + 8 y - 5) y

\frac{d y}{d y} = 1

\frac{d}{d y} (y^{3} + 8 y - 5) = 3 y^{2} + 8

= 1 \cdot (y^{3} + 8 y - 5) + (3 y^{2} + 8) y

Simplify

1 \cdot (y^{3} + 8 y - 5) + (3 y^{2} + 8) y : 4 y^{3} + 16 y - 5

= 4 y^{3} + 16 y - 5

\frac{( 3 x - L ) ( L + 3 x )}{18}

(x^{3} - 1) 3 x^{2} - 2 x

\frac{( 1 + x ) ^{2}}{2}

\frac{d ^{2}}{d k ^{2}} ((x) (e^{2 x} - k x))

\frac{1}{2 ( 12 a - 8 b )}

What is the d/(dy)((x)(x^3+8x-5)) ?
The d/(dy)((x)(x^3+8x-5)) is 4y^3+16y-5
What is the first d/(dy)((x)(x^3+8x-5)) ?
The first d/(dy)((x)(x^3+8x-5)) is 4y^3+16y-5