What is expand (10sin(θ)-3)^2 ?

The solution to expand (10sin(θ)-3)^2 is 100sin^2(θ)-60sin(θ)+9

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expand (10sin(θ)-3)^2

expand

(10 sin (θ) - 3)^{2}

100 sin^{2} (θ) - 60 sin (θ) + 9

Solution steps

(10 sin (θ) - 3)^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(10 sin (θ) - 3)^{2} = (10 sin (θ))^{2} - 2 \cdot 10 sin (θ) \cdot 3 + 3^{2}

= (10 sin (θ))^{2} - 2 \cdot 10 sin (θ) \cdot 3 + 3^{2}

Simplify

(10 sin (θ))^{2} - 2 \cdot 10 sin (θ) \cdot 3 + 3^{2} : 100 sin^{2} (θ) - 60 sin (θ) + 9

= 100 sin^{2} (θ) - 60 sin (θ) + 9

((2 (t^{2} + 1)^{2}), - t (t^{2} + 1)) \cdot (1, 2 t)

\frac{- x ^{2} - 3 x - 10}{( x + 2 ) ( x + 4 ) ( x - 2 )}

e^{x} (x^{2} + 2 x)

- 2 (x + 1) (u^{'} (x) + H (x))

\frac{\frac{d}{d x} ( ( x + 2 ) ( x - 1 ) )}{x ^{3} - 1}

What is expand (10sin(θ)-3)^2 ?
The solution to expand (10sin(θ)-3)^2 is 100sin^2(θ)-60sin(θ)+9