What is expand-2(x+1)(u'(x)+\H(x)) ?

The solution to expand-2(x+1)(u'(x)+\H(x)) is -2xu'(x)-2x\H(x)-2u'(x)-2\H(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-2(x+1)(u'(x)+\H(x))

expand

- 2 (x + 1) (u^{'} (x) + H (x))

- 2 xu' (x) - 2 x H (x) - 2 u' (x) - 2 H (x)

Solution steps

- 2 (x + 1) (u^{'} (x) + H (x))

Expand

(x + 1) (u^{'} (x) + H (x)) : x u^{'} (x) + x H (x) + u^{'} (x) + H (x)

= - 2 (x u^{'} (x) + x H (x) + u^{'} (x) + H (x))

Expand

- 2 (x u^{'} (x) + x H (x) + u^{'} (x) + H (x)) : - 2 x u^{'} (x) - 2 x H (x) - 2 u^{'} (x) - 2 H (x)

= - 2 x u^{'} (x) - 2 x H (x) - 2 u^{'} (x) - 2 H (x)

\frac{\frac{d}{d x} ( ( x + 2 ) ( x - 1 ) )}{x ^{3} - 1}

\frac{( x + 1 ) ( x - 3 ) 3}{( x + 4 ) ( x - 1 )}

\frac{( x ^{2} + 2 ) d x}{x ^{3} - 7 x ^{2} + 10 x}

\frac{x ( 10 - x ^{2} )}{2}

\frac{x A + B + 4 A}{( x - 1 ) ( x - 3 )}

What is expand-2(x+1)(u'(x)+\H(x)) ?
The solution to expand-2(x+1)(u'(x)+\H(x)) is -2xu'(x)-2x\H(x)-2u'(x)-2\H(x)