What is expand ((6x^2+2)(3x-8))/3 ?

The solution to expand ((6x^2+2)(3x-8))/3 is 6x^3-16x^2+2x-16/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((6x^2+2)(3x-8))/3

expand

\frac{( 6 x ^{2} + 2 ) ( 3 x - 8 )}{3}

6 x^{3} - 16 x^{2} + 2 x - \frac{16}{3}

Solution steps

\frac{( 6 x ^{2} + 2 ) ( 3 x - 8 )}{3}

Expand

(6 x^{2} + 2) (3 x - 8) : 18 x^{3} - 48 x^{2} + 6 x - 16

= \frac{18 x ^{3} - 48 x ^{2} + 6 x - 16}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{18 x ^{3} - 48 x ^{2} + 6 x - 16}{3} = \frac{18 x ^{3}}{3} - \frac{48 x ^{2}}{3} + \frac{6 x}{3} - \frac{16}{3}

= \frac{18 x ^{3}}{3} - \frac{48 x ^{2}}{3} + \frac{6 x}{3} - \frac{16}{3}

Divide the numbers:

\frac{18}{3} = 6

= 6 x^{3} - \frac{48 x ^{2}}{3} + \frac{6 x}{3} - \frac{16}{3}

Divide the numbers:

\frac{48}{3} = 16

= 6 x^{3} - 16 x^{2} + \frac{6 x}{3} - \frac{16}{3}

Divide the numbers:

\frac{6}{3} = 2

= 6 x^{3} - 16 x^{2} + 2 x - \frac{16}{3}

\frac{\partial}{\partial x} ((z) (9 - x^{2} - y^{2}))

(y + 2 x y^{3}) d x + (1 + 3 x^{2} y^{2} + x) d y

(1 - 2 sin (θ))^{2}

6.16 + 0.22 e^{- e^{(- 0.65) (t - 1.22)}}

(x - 2) lo g_{2} (3) - 3 x

What is expand ((6x^2+2)(3x-8))/3 ?
The solution to expand ((6x^2+2)(3x-8))/3 is 6x^3-16x^2+2x-16/3