What is expand (1+4sin(t))(4cos(t)) ?

The solution to expand (1+4sin(t))(4cos(t)) is 4cos(t)+16cos(t)sin(t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (1+4sin(t))(4cos(t))

expand

(1 + 4 sin (t)) (4 cos (t))

4 cos (t) + 16 cos (t) sin (t)

Solution steps

(1 + 4 sin (t)) (4 cos (t))

= (4 cos (t)) (1 + 4 sin (t))

Apply the distributive law:

a (b + c) = ab + a c

(4 cos (t)) (1 + 4 sin (t)) = 4 cos (t) \cdot 1 + 4 cos (t) \cdot 4 sin (t)

= 4 cos (t) \cdot 1 + 4 cos (t) \cdot 4 sin (t)

Simplify

4 cos (t) \cdot 1 + 4 cos (t) \cdot 4 sin (t) : 4 cos (t) + 16 cos (t) sin (t)

= 4 cos (t) + 16 cos (t) sin (t)

(x_{0} + α x_{1})^{3}

(e^{- x^{2}} - 2 e^{- x^{2}} x^{2})^{2}

(f \circ g) (2 x^{2} + x)

\frac{( 4 x + 1 ) ^{2}}{( x - 2 ) ( x + 3 )}

d x [x (5 x^{4} - 7 x^{2} - 3)]

What is expand (1+4sin(t))(4cos(t)) ?
The solution to expand (1+4sin(t))(4cos(t)) is 4cos(t)+16cos(t)sin(t)