What is expand (+3-6+9=0,)(-4+7+2=0) ?

The solution to expand (+3-6+9=0,)(-4+7+2=0) is 15=0

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expand (+3-6+9=0,)(-4+7+2=0)

expand

(+ 3 - 6 + 9 = 0,) (- 4 + 7 + 2 = 0)

15 = 0

Solution steps

(3 - 6 + 9 = 0,) (- 4 + 7 + 2 = 0)

= (3 - 6 + 9 \cdot 0 =,) (- 4 + 7 + 2 \cdot 0 =)

Distribute parentheses

3 (- 4) + 3 \cdot 7 + 3 \cdot 2 = 0 + (- 6) (- 4) + (- 6) \cdot 7 + (- 6) \cdot 2 = 0 + 9 = 0, (- 4) + 9 = 0, 7 + 9 = 0, 2 = 0

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

- 3 \cdot 4 + 3 \cdot 7 + 3 \cdot 2 = 0 + 6 \cdot 4 - 6 \cdot 7 - 6 \cdot 2 = 0 - 9 = 0, 4 + 9 = 0, 7 + 9 = 0, 2 = 0

Expand

- 3 \cdot 4 + 3 \cdot 7 + 3 \cdot 2 : 15

15 = 0

f (3) + (x - 3) f^{'} (3)

(x + 1) ln^{2} (x + 1)

(1 + 2)^{3}

sin (x) cos (π) - cos (x) sin (π)

\frac{8 - 3 x}{3 x ^{\frac{1}{3}} ( 4 - x ) ^{\frac{5}{3}}}

What is expand (+3-6+9=0,)(-4+7+2=0) ?
The solution to expand (+3-6+9=0,)(-4+7+2=0) is 15=0